Estimate The Car's Velocity At 4.0 S . Express Your Answer To Two Significant Figures And Include The (2024)

The two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder

What are the two reactant forces on the ladder?

To know the reactant forces on the ladder, we use Newton's third law of motion.

What is Newton's third law of motion?

Newton's third law of motion states that for every action, there is an equal and opposite reaction.

So, for the ladder, as the ladder leans against a wall it exerts a force on both the wall and ground.

Now, since the ladder exerts a force on the wall, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the wall is Fladder on wall, then the reaction force of wall on the ladder is Fwall on ladder.

So, Fladder on wall = -Fwall on Ladder

Also, since the ladder exerts a force on the ground, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the ground is Fladder on ground, then the reaction force of ground on the ladder is Fground on ladder.

So, Fladder on ground = -Fground on Ladder

So, the two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder

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Answer: 1.2 mm

Explanation:

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement= 0.5* (2.4/140) *140 = 1.2 mm

The volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

We know that,

ρ = m / V

where,

ρ = Density

m = Mass

V = Volume

Given that,

ρ = 45 g / ml

m = 855 g

V = 855 / 45

V = 19 ml

Density is the measure of amount of molecules present in substance. It is denoted by ρ. Its unit is usually g / ml.

Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

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The vertical speed of the ball increases and its horizontal speed remains constant as usual because air friction is being neglected.

By definition, air resistance refers to the forces that work against an object's relative motion as it travels through the atmosphere. These drag forces cause the object to move more slowly by acting in opposition to the speed of the incoming flow. Since drag is the part of the net aerodynamic force operating in the opposite direction to the direction of the movement, it differs from other resistance forces in that it directly depends on velocity.

Fluid friction includes friction in the air. These friction forces differ from the conventional model of surface friction in that they rely on velocity. Only rare examples can be dealt with analytically since the velocity dependence may be extremely intricate. Air resistance is roughly proportional to velocity and can be represented in the form of very low speeds for microscopic particles.

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Which of the following must happen in order for atoms to bond either ionically or covalently with one another?

a: The valence shells of all atoms must be filled after the bonding occurs

In order for atoms to bond either ionically or covalently with one another the valence shells of all atoms must be filled after the bonding occurs.

What is an atom?

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer:

D- Interference

Explanation:

When two waves meet they interfere with one another resulting in Interference

When body is changing its velocity at a constant rate then the body is said to be in uniform acceleration.

When a body is changing its velocity at different rates than my body is said to be moving with non uniform acceleration.

acceleration - The rate of change of velocity with respect to time.

It is a vector quantity.

a = dv / dt

SI unit is m/s²

direction of acceleration is the direction of change in velocity.

types of acceleration

uniform accelerationnon uniform accelerationinstantaneous acceleration

When body is changing its velocity at a constant rate then the body is said to be in uniform acceleration.

When a body is changing its velocity at different rates than my body is said to be moving with non uniform acceleration.

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[tex]We \: know \: that, \: c = λv \\ thus \: \: λ = \frac{c}{v} = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{94.7 \times {10}^{6} } \\ = 3.16789863≈3.17 \: m[/tex]

Hope this helps :)

Explanation:

[tex]{ \rm{ \vec{B}} = \frac{ \mu_{0}N}{l} } \\ [/tex]

N is number of turns

l is conductor length

mu_0 is permeability

[tex]{ \boxed{ \tt{ \mu_{0} = 4\pi \times {10}^{ - 7} }}}[/tex]

#include <stdio.h>

int main()

{

const int LENGTH = 10;

const int WIDTH = 5;

const char NEWLINE = '\n';

int area;

area = LENGTH * WIDTH;

printf("value of area : %d", area);

printf("%c", NEWLINE);

return 0;

}

The equation for centripetal acceleration is:

[tex]A = \frac{V^{2} }{R}[/tex]

Centripetal acceleration is the rate at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

The equation for centripetal acceleration is:

[tex]A = \frac{V^{2} }{R}[/tex]

therefore, the centripetal acceleration, denoted by the symbol A, has a magnitude equal to the square of the body's velocity along the curve divided by the radius of the circle, denoted by the symbol r. Units for centripetal acceleration are metres per second squared.

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Answer:

All the cells in an organism have exactly the same function

We consider an elementary mass located at this point to be in a stable equilibrium.

What is stable equilibrium?

An equilibrium is said to be stable if small, externally induced displacements from that state produce forces that tend to oppose the displacement and return the body or particle to the equilibrium state.

Also a body is said to be in a stable equilibrium, if the opposing forces acting on a body are equal.

Examples of a stable equilibriuma weight suspended by a springa brick lying on a level surfacea cone resting on its base

Thus, along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point to be in a stable equilibrium.

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The age of the sample will be 11460 years.

The half-life of C-14 = 5730 years.

The half- life time is the time taken by the object to attain its position till the half of its initial value.

i.e after 5730 years only half of the C-14 carbon will exists.

To retain one-fourth of the sample, another cycle of 5730 years is required.

This means 2 half-lives should have passed to retain one-fourth of the sample.

so to calculate it's age

[tex]\frac{t}{\frac{t}{\frac{1}{2} } }[/tex] = 2

where t = the age of the sample

with t(1/2) = the half-life time of the sample = 5470 years

2 = the number of half- lives passed

therefore

[tex]\frac{t}{5730}[/tex] = 2

t = 2*5730 = 11460 years

When only one-fourth of the sample will remain, the age of the sample will be 11460 years

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Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

How far did the driver travel during the inattentive period?

Speed is simply referred to as distance traveled per unit time.

Mathematically, Speed = Distance ÷ time.

Given the data in the question;

Speed = 80 km/hTime = 1.7sDistance travelled = ?

First, convert 1.7 seconds to hours.

Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs

Now, find the distance traveled during the inattentive period.

80 km/h = Distance ÷ 1.7/3600 hrs

Distance = 80 km/h × 1.7/3600 hrs

Distance = 136/3600 km

Distance = 0.037 km.

Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.

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Taking into account the Universal Law of Gravitation, the magnitude of the gravitational attraction between the books is 2.86×10⁻⁸ N.

Universal Law of Gravitation

The Universal Law of Gravitation establishes that bodies experience a force of attraction towards other bodies with mass, called gravitational force.

The Universal Law of Gravitation states that the gravitational force between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distance that separates them.

Mathematically it is expressed as follows:

[tex]F=G\frac{Mm}{d^{2} }[/tex]

where:

G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ [tex]\frac{Nm^{2} }{kg^{2} }[/tex].M and m are the masses of the bodies that interact.d is the distance that separates them.

Magnitude of the gravitational attraction between the books

In this case, you know:

G= 6.67×10⁻¹¹ [tex]\frac{Nm^{2} }{kg^{2} }[/tex]M= m= 2.9 kgd= 0.14 m

Replacing in the Universal Law of Gravitation:

[tex]F=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{2.9 kgx2.9 kg}{(0.14 m)^{2} }[/tex]

Solving:

[tex]F=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{8.41 kg^{2} }{0.0196 m^{2} }[/tex]

F= 2.86×10⁻⁸ N

Finally, the magnitude of the gravitational attraction between the books is 2.86×10⁻⁸ N.

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Answer:

[tex]Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\[/tex]

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash, therefore the correct answer is option A.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem, a test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.

Thus, the initial acceleration vector will point in the direction of the wall and be smaller than the crash's acceleration vector, therefore the correct answer is option A.

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Answer:

200N in Player 1's direction

Player 2 is knocked back

Explanation:

Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.

Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]

Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]

They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]

Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.

Hope this helped!

It will take the fugitive 4.83 s to catch the empty box car

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the time

The time taken for the fugitive to catch the car if he maintains his maximum speed can be obtained as follow:

Initial velocity (u) = 0 m/sAcceleration (a) = 1.2 m/s² Final velocity (v) = 5.8 m/sTime (t) =?

a = (v – u) / t

Thus,

t = (v – u) / a

t = (5.8 – 0) / 1.2

t = 5.8 / 1.2

t = 4.83 s

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Answer:

.................

Explanation:

....

...............

A free body diagram of the box consists of weight of the box (50N) acting downwards, normal reaction acting upwards and applied force acting in x-direction.

What is free body diagram?

A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown.

The forces on the box;

applied force, acting forward, F = 170 Nweight of the box, acting downwards, W = 50 Nnormal reaction of the box acting upwards, R = W = 50 N

The free body diagram of the forces acting on the box is illustrated as follows;

↑ R

F → Ф

↓ W

Thus, a free body diagram of the box consists of weight of the box (50N) acting downwards, normal reaction acting upwards and applied force acting in x-direction.

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Answer:

A

Explanation:

When switches 1 and 2 are 'on' or 'closed' the circuit becomes a short

Answer:

58.8 metres

Explanation:

using the formula

h=ut+½gt

U=0

g=9.8m/s²

t=12.0a

Hence, h= 0.5 × 9.8 × 144

h = 58.8 metres

Answer: x=-22

Explanation:

f=final position

-45=f-23

-45+23=f

f=-22

x=-22

Answer:

B. Fog forms in a valley.

Explanation:

The maximum height above the point of contact with the bat that the ball would reach would be 88.72 meters

What is a projectile motion?

It is the movement of any item or body when it is launched from the the earth's surface and follows any curving course while being affected by the gravitational pull of the planet.

The maximum height of the projectile motion is given by,

Maximum height = v² sin²θ / 2 g

=45² sin² 68/ 2 *9.81

=88.72 meters

Thus, the maximum height the ball would reach would be 88.72 meters

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The radius of the disc will be 0.496 meters.

What is Angular velocity?

The pace at which an object rotates or revolves around an axis is known as its angular velocity. The Greek letter omega stands for angular velocity. Because it is expressed as an angle per unit of time, angular velocity in the SI is measured in radians per second. [[tex]M^{0}L^{0}T^{-1}[/tex]] is the dimensional formula for angular velocity.

According to the question, the given values are :

Acceleration, a=4.9 m/s² and,

Period of rotation, T=2.0 seconds

So, angular velocity (ω) of disc =2π/T

⇒2π/2

= π rad/sec.

Acceleration= rω²

4.9= r×π²

r=0.496 meters.

Hence, the radius of the disc will be 0.496 meters.

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Answer:

okay

Explanation:

why don't you have any question in this app?