Physics College

## Answers

**Answer 1**

Answer- V≈75(m/s)

—(v=x/t) velocity is equal to distance, or x, over time, or t. at t=4, x is approximately equal to 300. therefore you would divide 300 by 4, getting 75

## Related Questions

As a ladder leans against a wall it exerts a force on both the wall and ground. What are the two reactant forces on the ladder?

Responses

−Fwall on ladder and −Fground on ladder

−Fwall on ladder and −Fground on ladder

upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

Fwall on ladder and −Fground on ladder

Fwall on ladder and −Fground on ladder

upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

Fwall on ladder and Fground on ladder

Fwall on ladder and Fground on ladder

upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline

−Fwall on ladder and Fground on ladder

−Fwall on ladder and Fground on ladder

Its -Fwallonladdy and -fgroundonladder just made sure to add this since no one else did yet

### Answers

The two** reactant forces** on the ladder are -Fwall on Ladder and -Fground on Ladder

What are the two reactant forces on the ladder?

To know the **reactant forces **on the ladder, we use Newton's third law of motion.

What is Newton's third law of motion?

**Newton's third law** of **motion** states that for every action, there is an equal and opposite reaction.

So, for the ladder, as the ladder leans against a wall it exerts a force on both the wall and ground.

Now, since the ladder exerts a force on the wall, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the wall is Fladder on wall, then the **reaction force** of wall on the ladder is Fwall on ladder.

So, Fladder on wall = -Fwall on Ladder

Also, since the ladder exerts a force on the ground, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the ground is Fladder on ground, then the **reaction force **of ground on the ladder is Fground on ladder.

So, Fladder on ground = -Fground on Ladder

So, the two** reactant forces** on the ladder are -Fwall on Ladder and -Fground on Ladder

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At the snail racing championship in England, the winner moved at an average velocity of 2.4 mm/s [fwd] for 140 s. Determine the winning snail’s displacement during this time interval.

### Answers

**Answer: 1.2 mm**

**Explanation:**

Time= 140 sec

Initial Velocity= 0

Average Velocity= 2.4 mm/s

Displacement= 0.5* (2.4/140) *140 = 1.2 mm

What is the volume of a rock with a density of 45 g/mL and a mass of 855 grams?

Your answer must have units

### Answers

The **volume **of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml

We know that,

**ρ = m / V**

where,

ρ = Density

m = Mass

V = Volume

Given that,

ρ = 45 g / ml

m = 855 g

V = 855 / 45

V = 19 ml

Density is the measure of **amount of molecules** present in substance. It is denoted by ρ. Its unit is usually g / ml.

Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is **19 ml**

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A baseball player throws a ball horizontally.

Which statement best describes the ball's

motion after it is thrown? [Neglect the effect of

friction.]

### Answers

The vertical speed of the ball increases and its horizontal speed remains constant as usual because air** friction** is being neglected.

By definition, air resistance refers to the forces that work against an object's relative motion as it travels through the atmosphere. These drag forces cause the object to move more slowly by acting in opposition to the speed of the incoming flow. Since drag is the part of the net aerodynamic force operating in the opposite direction to the direction of the movement, it differs from other resistance forces in that it directly depends on velocity.

Fluid **friction** includes **friction** in the air. These **friction** forces differ from the conventional model of surface **friction** in that they rely on velocity. Only rare examples can be dealt with analytically since the velocity dependence may be extremely intricate. Air resistance is roughly proportional to velocity and can be represented in the form of very low speeds for microscopic particles.

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HELP ASAP

Referring to the map of the temperature field in the room, what was the largest variation in temperature?

1.) 2 degrees

2.) 4 degrees

3.) 1 degree.

4.) none of the above

### Answers

None of above

57.2c would be the answer i believe

Which of the following must happen in order for atoms to bond either ionically or covalently with one another?

A The valence shells of all atoms must be filled after the bonding occurs

b The chemical properties of the atoms must be satisfied

c The ions must have different charges

d The resulting compound must follow ionic naming conventions

### Answers

Which of the following must happen in order for atoms to bond either ionically or covalently with one another?

a: The valence shells of all atoms must be filled after the bonding occurs

In order for **atoms** to bond either ionically or covalently with one another the **valence shells** of all atoms must be filled after the bonding occurs.

What is an atom?

An **atom **is defined as the smallest unit of** matter** which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The** protons **are positively charged and **neutrons** are neutral and hence the nucleus is positively charged. The** electrons** which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of **sub- atomic particles** which on combination do not alter the** chemical properties **of the substances.

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PLS HELP. What is the result of two waves meeting each other?

A. diffraction

B. reflection

C. refraction

D. interference

### Answers

**Answer:**

D- Interference

**Explanation:**

When two waves meet they interfere with one another resulting in Interference

The answer to your question is D. Interference

When will you say a body is in Uniform acceleration and Non Uniform acceleration?

### Answers

When body is changing its velocity at a constant rate then the body is said to be in **uniform acceleration.**

When a body is changing its velocity at different rates than my body is said to be moving with **non uniform acceleration.**

**acceleration **- The rate of change of **velocity **with respect to** time.**

It is a vector quantity.

a = dv / dt

SI unit is m/s²

direction of **acceleration **is the direction of **change in velocity.**

**types **of acceleration

uniform accelerationnon uniform accelerationinstantaneous acceleration

When body is changing its velocity at a constant rate then the body is said to be in **uniform acceleration.**

When a body is changing its velocity at different rates than my body is said to be moving with **non uniform acceleration.**

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If a radio wave has speed 3.00 *10^8 m/s and frequency 94.7 MHz, what is its wavelength?

### Answers

[tex]We \: know \: that, \: c = λv \\ thus \: \: λ = \frac{c}{v} = \frac{3 \times {10}^{8} \: m {s}^{ - 1} }{94.7 \times {10}^{6} } \\ = 3.16789863≈3.17 \: m[/tex]

*Hope** **this** **helps** **:**)*

what is the general formula for measuring [tex] \vec{B} [/tex] , i.e. , magnetic field intensity ?

tysm ;-;

### Answers

**Explanation:**

[tex]{ \rm{ \vec{B}} = \frac{ \mu_{0}N}{l} } \\ [/tex]

N is number of turns

l is conductor length

mu_0 is permeability

[tex]{ \boxed{ \tt{ \mu_{0} = 4\pi \times {10}^{ - 7} }}}[/tex]

#include <stdio.h>

int main()

{

const int LENGTH = 10;

const int WIDTH = 5;

const char NEWLINE = '\n';

int area;

area = LENGTH * WIDTH;

printf("value of area : %d", area);

printf("%c", NEWLINE);

return 0;

}

Suppose you are told that acceleratioon A with of particle moving with uniform sleep v in a circle of radius R is proportional to same power of r(r) and same power of V. Determine the radius of A in and write the Simple form of equation for the acceleratioon

### Answers

The equation for** centripetal acceleration** is:

[tex]A = \frac{V^{2} }{R}[/tex]

**Centripetal acceleration **is the rate at which a body moves through a circle. Due to the fact that **velocity** is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in** velocity**, which results in an acceleration.

The equation for** centripetal acceleration** is:

[tex]A = \frac{V^{2} }{R}[/tex]

therefore, the **centripetal acceleration**, denoted by the symbol A, has a magnitude equal to the square of the body's **velocity** along the curve divided by the radius of the circle, denoted by the symbol r. Units for **centripetal acceleration** are metres per second squared.

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Which statement is NOT part of the Cell theory? All cells come from other cells. All cells come from other cells., All organisms are composed of cells. All organisms are composed of cells., Cells are the basic living units of organization in all organisms. Cells are the basic living units of organization in all organisms., EndFragment, All the cells in an organism have exactly the same function

### Answers

**Answer:**

All the cells in an organism have exactly the same function

HELP! Along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point. How can this state be rated? Stable equilibrium, unstable equilibrium, total mechanical energy minimum, total mechanical energy maximum or minimum

### Answers

We consider an elementary mass located at this point to be in a **stable equilibrium.**

**What is stable equilibrium?**

An **equilibrium** is said to be stable if small, externally induced displacements from that state produce forces that tend to oppose the displacement and return the body or particle to the equilibrium state.

Also a body is said to be in a **stable equilibrium**, if the opposing forces acting on a body are equal.

Examples of a stable equilibriuma weight suspended by a springa brick lying on a level surfacea cone resting on its base

Thus, along the line through the centers of the Moon and the Earth, there is a point where the** gravitational forces** exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point to be in a **stable equilibrium.**

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Carbon14 has half life of 5,730 years. If an archaeological sample has only one-fourth of the radioactivity of a similar sample from today how old is the archaeological sample

### Answers

The age of the sample will be 11460 years.

The **half-life** of C-14 = 5730 years.

The half- life time is the time taken by the object to attain its position till the half of its initial value.

i.e after 5730 years only half of the **C-14 carbon** will exists.

To retain **one-fourth** of the sample, another cycle of 5730 years is required.

This means 2 half-lives should have passed to retain one-fourth of the sample.

so to calculate it's age

[tex]\frac{t}{\frac{t}{\frac{1}{2} } }[/tex] = 2

where t = the age of the sample

with t(1/2) = the half-life time of the sample = 5470 years

2 = the number of half- lives passed

therefore

[tex]\frac{t}{5730}[/tex] = 2

t = 2*5730 = 11460 years

When only one-fourth of the sample will remain, the age of the sample will be **11460 years**

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If you are driving 80 km/h along a straight road and you look to the side for 1.7 s , how far do you travel during this inattentive period?

Express your answer using two significant figures.

### Answers

Given the speed of the **driver **and the time elapsed, **distance traveled **during his **inattentive period **is **0.037 kilometers.**

How far did the driver travel during the inattentive period?

**Speed **is simply referred to as **distance traveled **per **unit time**.

Mathematically, **Speed **= **Distance **÷ **time**.

Given the data in the question;

Speed = 80 km/hTime = 1.7sDistance travelled = ?

First, **convert **1.7 **seconds **to **hours**.

Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs

Now, find the **distance traveled **during the **inattentive period**.

80 km/h = Distance ÷ 1.7/3600 hrs

Distance = 80 km/h × 1.7/3600 hrs

Distance = 136/3600 km

**Distance = 0.037 km.**

Given the speed of the **driver **and the time elapsed, **distance traveled **during his **inattentive period **is **0.037 kilometers.**

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Two 2.9 kg physical science textbooks on a bookshelf are 0.14 m apart. What is the magnitude of the gravitational attraction between the books?

### Answers

Taking into account the Universal Law of Gravitation, the **magnitude of the gravitational attraction** between the books is **2.86×10⁻⁸ N**.

Universal Law of Gravitation

The Universal Law of Gravitation establishes that **bodies **experience a **force of attraction **towards other bodies with mass, called **gravitational force**.

The Universal Law of Gravitation states that the **gravitational force** between two bodies is **directly proportional** to the **product of their masses **and** inversely proportional** to the **square of the distance** that separates them.

**Mathematically** it is expressed as follows:

[tex]F=G\frac{Mm}{d^{2} }[/tex]

where:

G is the universal gravitational constant, with a value of 6.67×10⁻¹¹ [tex]\frac{Nm^{2} }{kg^{2} }[/tex].M and m are the masses of the bodies that interact.d is the distance that separates them.

Magnitude of the gravitational attraction between the books

In this case, **you know**:

G= 6.67×10⁻¹¹ [tex]\frac{Nm^{2} }{kg^{2} }[/tex]M= m= 2.9 kgd= 0.14 m

**Replacing** in the Universal Law of Gravitation:

[tex]F=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{2.9 kgx2.9 kg}{(0.14 m)^{2} }[/tex]

Solving:

[tex]F=6.67x10^{-11}\frac{Nm^{2} }{kg^{2} } \frac{8.41 kg^{2} }{0.0196 m^{2} }[/tex]

*F= 2.86×10⁻⁸ N*

Finally, the **magnitude of the gravitational attraction** between the books is **2.86×10⁻⁸ N**.

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If a ball leaves the ground with a velocity of 4.67 m/s,

how high does the ball travel?

### Answers

**Answer:**

[tex]Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\[/tex]

A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.

Question 8 options:

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash.

The direction of the initial acceleration vector will point away from the wall, and its magnitude will be more than the acceleration vector of the crash.

The direction of the initial acceleration vector will point away from the wall, and its magnitude will be less than the vector of the crash.

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be more than the acceleration vector of the crash.

### Answers

The **direction **of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration **vector **of the crash, therefore the correct answer is option A.

What is acceleration?

The rate of **change **of the velocity with respect to time is known as the acceleration of the object.

As given in the problem, a test car carrying a **crash **test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the **direction **of the initial acceleration vector and compare the initial acceleration **vector's **magnitude with respect to the crash acceleration magnitude.

Thus, the initial **acceleration **vector will point in the direction of the wall and be **smaller **than the crash's acceleration vector, therefore the correct answer is option A.

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Two football players hit each other head on in a football game. One football

player had an acceleration of 4 m/s² and a mass of 150 kg. The second football

player had an acceleration of 2 m/s² and a mass of 200 kg. Calculate the force

each player had when they hit. What will be the net force of both players and who

knocked who back.

### Answers

**Answer:**

200N in Player 1's direction

Player 2 is knocked back

**Explanation:**

Let's start by working out the force exerted by each player by using the equation F=ma, Force = Mass x Acceleration.

Player 1 has an acceleration of 4m/s2 and a mass of 150kg, therefore their force will be: [tex]F = (150)(4)[/tex], [tex]F=600N[/tex]

Player 2 has an acceleration of 2m/s2 and a mass of 200kg, therefore their force will be: [tex]F = (200)(2)[/tex], [tex]F=400N[/tex]

They are both coming from different directions so we can find the net force by subtracting one from the other: [tex]600-400=200N[/tex]

Player 1 has the higher force so the net force will be 200N in the direction Player 1 is travelling in and Player 2 will be the one knocked back.

Hope this helped!

A fugitive tries to hop on a freight train traveling at a constant speed of 5.2 m/s. Just as an empty box car passes him,the fugitive starts from rest and accelerates at a =1.2 m/s^2 to his maximum speed of 5.8 m/s, which he then maintains. How long does it take him to catch up to the empty box car?

### Answers

It will take the fugitive **4.83 s** to catch the empty box car

What is acceleration?

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a is the acceleration v is the final velocity u is the initial velocity t is the time

How to determine the time

The **time taken** for the fugitive to catch the car if he maintains his maximum speed can be obtained as follow:

Initial velocity (u) = 0 m/sAcceleration (a) = 1.2 m/s² Final velocity (v) = 5.8 m/s**Time (t) =?**

a = (v – u) / t

Thus,

t = (v – u) / a

t = (5.8 – 0) / 1.2

t = 5.8 / 1.2

**t = ****4****.****8****3**** s**

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PLEASE help me with this problem??!!

### Answers

Correct option is more then 44 hours.

If the radius of a sphere increases by a factor of 2.50, by what factor does the volume of the sphere change?

### Answers

**Answer:**

.................

**Explanation:**

....

...............

an upward force of 170 N IS APPLIED TO A BOX WEIGHING 50 N DRAW A FREEBODY FORCE DIAGRAM FOR THIS SITUATION

### Answers

A **free body diagram** of the box consists of **weight** of the box (50N) acting downwards, **normal reaction** acting upwards and** applied force **acting in x-direction.

What is free body diagram?

A** free-body diagram** is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown.

The forces on the box;

applied force, acting forward, F = 170 Nweight of the box, acting downwards, W = 50 Nnormal reaction of the box acting upwards, R = W = 50 N

The **free body diagram** of the forces acting on the box is illustrated as follows;

↑ R

F → Ф

↓ W

Thus, a **free body diagram** of the box consists of **weight** of the box (50N) acting downwards, **normal reaction** acting upwards and** applied force **acting in x-direction.

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The circuit diagram below shows the locations of four switches. Which switch configuration creates a short circuit?

### Answers

**Answer:**

A

**Explanation:**

When switches 1 and 2 are 'on' or 'closed' the circuit becomes a short

An object dropped from the window of a tall building hits the ground in 12.0 s. If its acceleration is 9.80 m/s2, the height of the window above the ground is

### Answers

**Answer:**

58.8 metres

**Explanation:**

using the formula

h=ut+½gt

U=0

g=9.8m/s²

t=12.0a

Hence, h= 0.5 × 9.8 × 144

h = 58.8 metres

parar 7. Keira starts at position x = 23 m along a coordinate axis. She then undergoes a displacement of -45 m. What is her final position? nood A coordinate

### Answers

**Answer: **x=-22

**Explanation:**

f=final position

-45=f-23

-45+23=f

f=-22

**x=-22**

Which event is an example of condensation?

• A. A spilled drop of rubbing alcohol disappears.

O B. Fog forms in a valley.

• C. A puddle dries when exposed to the Sun.

D. A lake becomes a skating rink in the winter.

Correct answer B

### Answers

**Answer:**

B. Fog forms in a valley.

**Explanation:**

A baseball player hits a pop fly ball. If the ball leaves the bat at 45 m/s at an angle of 68° above the horizontal, what is the maximum height above the point of contact with the bat that the ball will reach? Ignore air resistance.

### Answers

The **maximum **height above the point of contact with the bat that the **ball **would reach would be 88.72 **meters**

What is a projectile motion?

It is the **movement **of any item or body when it is launched from the the earth's surface and follows any **curving **course while being affected by the **gravitational **pull of the planet.

The **maximum **height of the projectile motion is given by,

Maximum **height **= v² sin²θ / 2 g

=45² sin² 68/ 2 *9.81

=88.72 meters

Thus, the maximum **height **the ball would reach would be 88.72 **meters **

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A disc rotates about its axis at a constant rate. If the acceleration of the outer rim of the disc is 4.9 m/s2, and the period of the rotation is 2.0 s, what is the radius of the disc?

### Answers

The **radius** of the disc will be 0.496 meters.

What is Angular velocity?

The pace at which an object **rotates** or revolves around an axis is known as its **angular** velocity. The Greek letter omega stands for angular velocity. Because it is expressed as an angle per unit of **time**, angular velocity in the** SI **is measured in radians per second. [[tex]M^{0}L^{0}T^{-1}[/tex]] is the dimensional formula for angular **velocity**.

According to the question, the given values are :

**Acceleration**, a=4.9 m/s² and,

Period of **rotation**, T=2.0 seconds

So, angular velocity (ω) of **disc** =2π/T

⇒2π/2

= π rad/sec.

**Acceleration**= rω²

4.9= r×π²

r=0.496 meters.

Hence, the radius of the **disc **will be 0.496 meters.

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i have no question d d d d

### Answers

**Answer:**

okay

**Explanation:**

why don't you have any question in this app?